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Answer by Rahul Mehta for VBA - how to conditionally skip a for loop iteration

VB6 , VBA doesnt have continue. Following HACK is what I have been using since VB3 days ie year 1992. I have been using "for dummy = 1 to 1 : exit for : next dummy" loop. The "exit for" inside dummy...

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Answer by AHeyne for VBA - how to conditionally skip a for loop iteration

You can use a kind of continue by using a nested Do ... Loop While False:'This sample will output 1 and 3 onlyDim i As IntegerFor i = 1 To 3: Do If i = 2 Then Exit Do 'Exit Do is the Continue...

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Answer by richo7 for VBA - how to conditionally skip a for loop iteration

Maybe try putting it all in the end if and use a else to skip the code this will make it so that you are able not use the GoTo. If 6 - ((Int_height(Int_Column - 1) - 1) + Int_direction(e, 1)) = 7 Or...

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Answer by Singaravelan for VBA - how to conditionally skip a for loop iteration

Hi I am also facing this issue and I solve this using below example codeFor j = 1 To MyTemplte.Sheets.Count If MyTemplte.Sheets(j).Visible = 0 Then GoTo DoNothing End If 'process for this for...

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Answer by Jon Egerton for VBA - how to conditionally skip a for loop iteration

Continue For isn't valid in VBA or VB6. From this MSDN page it looks to have been introduced into VB.Net in VS 2005./Net 2.As the others have said there's not really an option other than to use Goto or...

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Answer by mwolfe02 for VBA - how to conditionally skip a for loop iteration

VBA does not have a Continue or any other equivalent keyword to immediately jump to the next loop iteration. I would suggest a judicious use of Goto as a workaround, especially if this is just a...

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Answer by Brian for VBA - how to conditionally skip a for loop iteration

Couldn't you just do something simple like this?For i = LBound(Schedule, 1) To UBound(Schedule, 1) If (Schedule(i, 1) < ReferenceDate) Then PrevCouponIndex = i Else DF =...

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VBA - how to conditionally skip a for loop iteration

I have a for loop over an array. What I want to do is test for a certain condition in the loop and skip to the next iteration if true:For i = LBound(Schedule, 1) To UBound(Schedule, 1) If (Schedule(i,...

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